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# Your Problem: # Given an array of ints, compute recursively if the array contains somewhere # a value followed in the array by that value times 10. We'll use the # convention of considering only the part of the array that begins at the # given index. In this way, a recursive call can pass index+1 to move down # the array. The initial call will pass in index as 0. # # # array220({1, 2, 20}, 0) → true # array220({3, 30}, 0) → true # array220({3}, 0) → false # # Credit for this problem goes to Nick Parlante from CodingBat.com # Do not modify anything outside of the function or the function itself. # CODE START def getArray220(nums:List[int], index:int) -> bool: # CODE END # Press Ctrl+E (Command+E on mac) to test your code