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# Your Problem: # We have bunnies standing in a line, numbered 1, 2, ... The odd bunnies (1, # 3, ..) have the normal 2 ears. The even bunnies (2, 4, ..) we'll say have 3 # ears, because they each have a raised foot. Recursively return the number # of "ears" in the bunny line 1, 2, ... n (without loops or multiplication). # # # bunnyEars2(0) → 0 # bunnyEars2(1) → 2 # bunnyEars2(2) → 5 # # Credit for this problem goes to Nick Parlante from CodingBat.com # Do not modify anything outside of the function or the function itself. # CODE START def getBunnyEars2(n:int) -> int: # CODE END # Press Ctrl+E (Command+E on mac) to test your code