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# Your Problem: # Given n of 1 or more, return the factorial of n, which is n * (n-1) * (n-2) # ... 1. Compute the result recursively (without loops). # # # factorial(1) → 1 # factorial(2) → 2 # factorial(3) → 6 # # Credit for this problem goes to Nick Parlante from CodingBat.com # Do not modify anything outside of the function or the function itself. # CODE START def getFactorial(n:int) -> int: # CODE END # Press Ctrl+E (Command+E on mac) to test your code